1351. Count Negative Numbers in a Sorted Matrix - LeetCode Solution

class Solution:
    def countNegatives(self, grid: List[List[int]]) -> int:
        count = 0

        for i in range(len(grid)):
            for j in range(len(grid[i])):
                if grid[i][j] < 0:
                    count+=len(grid[i]) - j
                    break

        return count